Mathematics Tutor Trigonometric Functions -- 2

Hello, I am am graduate from the prestigious Indian Institute of Technology,Madras with a minor in Physics. I have done graduate level courses in mathematics like: measure theory, topology, Introduction to Algebraic Geometry, Introduction to Non-Linear Partial Differential equations. I have worked on a algebra assignment here on freelancer.com and received excellent feedback. I am also currently working on three other math related projects which speaks of my aptitude for math. 2 sin2(x-pi/6)=sqrt(3) => sin2(x-pi/6)=sqrt(3)/2 Theta can lie in first or second quadrant for this to be possible and sin x function is periodic with period 2pi so the general solution is: 2(x-pi/6)=2mpi+pi/6 ( First quadrant solutions ) 2(x-pi/6)=(2n+1)pi-pi/6 (Second Quadrant solutions) So the solutions are: -8pi/3 +5pi/2 -5pi/2 -5pi/3 +3pi/2 -3pi/2 -2pi/3 +pi/2 -pi/2 pi/3 4pi/3 7pi/3 Thanking You Dushyant Barot

Hi I can help you in understanding trigonometry. Solutions to your problem are [-16 -15 -10 -9 -4 -3 2 3 8 9 14 15]pi/6 Mohan

I am excellent in mathematics. I have gone through your project and I am sure that I can complete the project with accuracy and in time and provide you necessary support that required.

Answer to the example given is xe{π/3, 4π/3, 7π/3, -2π/3, -5π/3, -8π/3, π/2, 3π/2, 5π/2, -π/2, -3π/2, -5π/2} I'm a Physics and Mathematics teacher with over 15 years experience in tutoring.

Hi, I'm a math teacher and I have some successful projects, please see my profile: http://www.freelancer.com/u/klin.html Of course I can solve your equation... How you intend to do this tutoring online (skype/messenger) or using scanned images/pdfs... If you are interested to work with me, please contact me with/for more information. Thank you, Calin

the trignometric tutor is at your service............................................... In this problem use formula................ let, g = x -pi/6; and sin2(g) =2 sin ( g) *cos(g) check for boundary conditions when x= -3*pi ,then | and when x = 3*pi g = -3*pi - pi/6 = -19*pi / 6 | g = 3*pi - pi/6 =17*pi /6 replacing we get 2sin2(x - π/6) =2 sin (x - π/6) *cos(x - π/6) | 2sin2(x - π/6) =2 sin (x - π/6) *cos(x - π/6) =2 sin (-19*pi/6 ) *cos(-19pi/6 ) | =2 sin (17*pi /6) *cos(17*pi /6) =(-(3)^1/2) / 2= -0.866 | = -0.866 As you see that x varies from -3pi to 3pi , x again comes back to -0.866........So its a complete sine wave motion

Hello there, Without much ado on my academic background in Mathematics and my experience of teaching students, here is a bit of LaTeX code that you can use (in any LaTeX editor of choice) to view the (incomplete) solution to the problem. ************************************************************************************* 2\sin{\left (x-\frac{\pi}{6} \right )} = \sqrt{3} \text{ if } x \text{ } \epsilon \text { } [-3\pi, 3\pi] \Leftrightarrow \\ \sin{\left (x-\frac{\pi}{6} \right )} = \sqrt{\frac {3}{2}} \\ \\ \text{Let us replace } (x-\frac{\pi}{6}) \text{ by } \theta \text{ for convenience. Then, the previous equation turns into a much simpler one:} \\ \sin{\theta} = \sqrt{\frac {3}{2}} \text{, where } \theta \text{ } \epsilon \text{ }[-3\pi - \frac{\pi}{6}, 3\pi - \frac{\pi}{6}]. \\ \text{Then, the values of } \theta \text{ for which the equation } \sin{\theta} = \sqrt{\frac {3}{2}} \text { is satisfied are exactly those values of } \theta \text{ within the interval } [\frac{-19\pi}{6}, \frac{17\pi}{6}] \\ \text{ that are simply} \frac{\pi}{3} \text { or } \frac{2\pi}{3}, \pm2\pi \text{ informally}. \\ \sin{\theta} = \sqrt{\frac {3}{2}} \text{, where } \theta \text{ } \epsilon \text{ }[-3\pi - \frac{\pi}{6}, 3\pi - \frac{\pi}{6}]. \\ \text{Then, the values of } \theta \text{ for which the equation } \sin{\theta} = \sqrt{\frac {3}{2}} \text { is satisfied are exactly those values of } \theta \text{ within the interval } .... *****No more characters allowed.

There are 12 solutions to the problem you posted within the interval [-3 pi , 3 pi] All values below are multiplied by pi. pi * {-8/3 , -5/2, -5/3, -3/2, -2/3 , -1/4, 1/3, 1/2, 4/3, 3/2, 7/8, 5/2} =========================================================== I have a strong background in Mathematics, Statistics, Computer Science and Physics, having worked in them for many years for many companies. I also have professional experience with Matlab & Mathematica, having worked as as Matlab Mathematica Mathematics Consultant throughout my career. I have a Masters Degree in Mathematics from Purdue University, USA. I also provide tutoring, training, exam preparation, and assignment solution help in advanced college level Mathematics, Statistics, Physics and Computer Science courses. If given an opportunity I would put in my best effort to benefit you. I am ready to start work on your assignments today.

2 sin⁡〖2(x-π/3)=√3〗 =>sin⁡〖(2x-π/3)=√3/2〗 Basic Acute Angle= sin^(-1)⁡(√3/2) = π/3 The first and the second quadrants are where Sine is positive. So, 2x-π/3= π/3 ,(π-π/3),(2π+π/3),(2π+π-π/3),(2π+2π+π/3),(2π+2π+π-π/3), -(π+π/3),-(2π-π/3),-(2π+π+π/3),-(2π+2π-π/3),-(2π+2π+π+π/3), -(2π+2π+2π-π/3) Therefore, x= π/3 ,π/2 , 4π/3, 3π/2, 7π/3, 5π/2, -5π/6, -π, -11π/6, -2π, -17π/6, -3π (Answer) Dear Sir, Here is the solutions to the question that you wanted. Let me introduce myself to you: i am currently a university student in Bangladesh. i have completed my O level and A level under Edexcel IGCSE and GCE Edexcel which are under London curriculum. I am dedicated to provide you services at its maximum. You will always get the benefits that you require. Hope to get a positive reply from your end. Thank you Regards Ashir

hello sir, a mecha,ical engineer with high skills in math at ur service, kindly start messaging so we can discuss further details. i have the solution of this exemple

Hello! I recommend you to hire me for this project, since I am currently studying mathematics for the 5th year in the University of Helsinki, and we have gone through a lot of trigonometry. The example you have written is clear and quite easy to solve. I can provide you some help with the trigonometry, so that you will have a deeper understanding of this. Looking forward to your contact! Best regards, Anton.

Hello, michaelkress. I can help you with Trigonometry. I am an Electronic Engineer, and I like to teach Mathematics. My skype is juanca5301. I have the solution for the example that you have given. If you want, I will send the solution you (it's in a .pdf file ) through a private message.

Hello michaelkress, Its very nice to see your post, as you want to learn things, I am very good in mathematics and I have already taught books of advanced level mathematics to students. Trigonometry is an easiest and the most interesting branch of mathematics, if you want to clear your concepts in the area of mathematics you should give me a chance. Also we can decide hours and other things by mutual cooperation. Best of luck to you.

Hi I am not able to send you the solution... it says that I am not allow to start a thread until the employer starts

Hello. More 20 years mathematics and programming experience. How you imagine teaching process? skype? another? For your equation is enough to find solutions in [0, pi] segment, pi/4 and pi/3, and then take subset for [-3pi, 3pi] from recurring formul. Regards. ---------------------------------------------------------------------------------------------------------------------------------------------------

Given 2sin2(x - π/6) = sqrt(3) sin2(x - π/6) = sqrt(3)/2 sin2(x - π/6) = sinπ/3 2(x - π/6) = π/3 x - π/6 = π/6 x = π/3 similarly, we get more solutions for x in the interval [-3π, 3π]. For example, Take sin2(x - π/6) = sin2π/3, then we get x=π/2

Hi michaelkress, the answer is: x = 1.2-2*pi, 1.2, 1.2+2*pi, 1.2-3*pi please send the others. Thank you!!!

~Please consider my bid~ Dear Sir, I've read your project description and I would like to do it. I'm Ina and I'm a mathematical student. Now I'm doing my degree in Industrial Mathematics. I've learnt about trigonometric function before. I've tried to solve the given example and I get the value of x is π/3 or 60 degree. Is it the right answer? If yes, I would like to do this project. Do PM me for further discussion. Thank you.

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i am a engineering graduate and have a 2 yrs experience in handing this kind of tutorials.i believe in value for money.. plzz allot me this assignment and i wont disappoint u